WAEC - Mathematics (2003 - No. 35)
The square root of a number is 2k. What is half of the number
\(\sqrt{\frac{k}{2}}\)
\(\sqrt{k}\)
\(\frac{1}{2}k^2\)
2k2
Selitys
Let the number be x.
\(\sqrt{x} = 2k \implies x = (2k)^2\)
= \(4k^2\)
\(\frac{1}{2} \times 4k^2 = 2k^2\)