WAEC - Mathematics (2000 - No. 28)
Given that \(27^{(1+x)}=9,)\ find x
-3
\(\frac{-1}{3}\)
\(\frac{5}{3}\)
2
Selitys
\(27^{(1+x)}\) = 9
\(3^{3(1+x)} = 3^2\)
3(1+x) = 2
3 + 3x = 2
3x = -1
x = \(\frac{-1}{3}\)
\(27^{(1+x)}\) = 9
\(3^{3(1+x)} = 3^2\)
3(1+x) = 2
3 + 3x = 2
3x = -1
x = \(\frac{-1}{3}\)