WAEC - Mathematics (1999 - No. 15)
If \(y = \sqrt{ax-b}\) express x in terms of y, a and b
\(x = \frac{y^2-b}{a}\)
\(x = \frac{y+b}{a}\)
\(x = \frac{y-b}{a}\)
\(x = \frac{y^2 + b}{a}\)
Selitys
\(y = \sqrt{ax-b}\)
\(y^2 = ax-b\)
\(y^2 +b = ax\)
\(x = \frac{y^2 + b}{a}\)