WAEC - Mathematics (1998 - No. 1)
Find the root of the equation 2x\(^2\) - 3x - 2 = 0
x = -2 or 1/2
x = -2 or1
x = -2 or 2
x = -1 or 2
x = -1/2 or 2
Selitys
2x\(^2\) - 3x - 2 = 0
2x\(^2\) - 4x + x - 2 = 0
2x(x - 2) + 1(x - 2) = 0
(2x + 1)(x - 2) = 0
x = \(\frac{-1}{2}\) or x = 2