WAEC - Further Mathematics (2011 - No. 26)
In how many ways can 3 prefects be chosen out of 8 prefects?
6
24
56
336
Selitys
= \(^{8}C_{3} = \frac{8!}{(8 - 3)! 3!}\)
= \(\frac{8 \times 7 \times 6}{3 \times 2}\)
= 56 ways
= \(^{8}C_{3} = \frac{8!}{(8 - 3)! 3!}\)
= \(\frac{8 \times 7 \times 6}{3 \times 2}\)
= 56 ways