WAEC - Further Mathematics (2010 - No. 8)
If (x - 3) is a factor of \(2x^{2} - 2x + p\), find the value of constant p.
-12
-6
3
6
Selitys
Using remainder theorem, since x - 3 is a factor, then
given \(2x^{2} - 2x + p\), f(3) = 0
\(2(3^{2}) - 2(3) + p = 0 \implies 18 - 6 = -p\)
\(p = -12\)