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JEE Advance - Mathematics (2007 - No. 18)

If $$\left| z \right|\, =1\,and\,z\, \ne \, \pm \,1,$$ then all the values of $${z \over {1 - {z^2}}}$$ lie on
a line not passing through the origin
$$\left| z \right|\, = \,\sqrt 2 $$
the x-axis
the y-axis

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