JEE MAIN - Physics (2005 - No. 50)
A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be
four times
doubled
halved
one fourth
Selitys
$$H = {{{V^2}t} \over R}$$
Resistance of half the coil $$ = {R \over 2}$$
$$\therefore$$ As $$R$$ reduces to half, $$'H'$$ will be doubled.
Resistance of half the coil $$ = {R \over 2}$$
$$\therefore$$ As $$R$$ reduces to half, $$'H'$$ will be doubled.