JEE MAIN - Physics (2005 - No. 46)
A parallel plate capacitor is made by stacking $$n$$ equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is $$'C'$$ then the resultant capacitance is
$$\left( {n + 1} \right)C$$
$$\left( {n - 1} \right)C$$
$$nC$$
$$C$$
Selitys
As $$n$$ plates are joined, it means $$(n-1)$$ capacitor joined in parallel.
$$\therefore$$ resultant capacitance $$=(n-1)C$$
$$\therefore$$ resultant capacitance $$=(n-1)C$$