JEE MAIN - Physics (2004 - No. 17)
The total current supplied to the circuit by the battery is
$$4A$$
$$2A$$
$$1A$$
$$6A$$
Selitys
hence $${{\mathop{\rm R}\nolimits} _{eq}} = 3/2;$$
$$\therefore$$ $$I = {6 \over {3/2}} = 4A$$
hence $${{\mathop{\rm R}\nolimits} _{eq}} = 3/2;$$
$$\therefore$$ $$I = {6 \over {3/2}} = 4A$$