JEE MAIN - Physics (2002 - No. 63)
A cylinder of height $$20$$ $$m$$ is completely filled with water. The velocity of efflux of water (in $$m{s^{ - 1}}$$) through a small hole on the side wall of the cylinder near its bottom is
$$10$$
$$20$$
$$25.5$$
$$5$$
Selitys
The velocity of efflux of water is given $$v = \sqrt {2gh} $$
Here $$h$$ is the height of the free surface of water from the hole
$$\therefore$$ $$v = \sqrt {2 \times 10 \times 20} = 20m/s$$
Here $$h$$ is the height of the free surface of water from the hole
$$\therefore$$ $$v = \sqrt {2 \times 10 \times 20} = 20m/s$$