JAMB - Physics (2024 - No. 88)
A body is pulled on a horizontal surface with a rope inclined at 30º to the vertical. If the effective force pulling the body along the horizontal surface is 15N, calculate the tension on the rope.
30N
60N
22.5N
75N
Selitys
Effective horizontal force = 15N
T = tension on the rope
F\(_x\) = T sin\(\theta\)
15 = T x sin 30º
T = \(\frac{15}{0.5}\) = 15 x 2 = 30N.