JAMB - Physics (2010 - No. 32)
The ground stated energy for the hydrogen atom is 5.44 x 10-19J . If an electron drops from zero energy to ground state, calculate the frequency of the emitted radiation?
[h = 6.6 x 10-34 Js]
[h = 6.6 x 10-34 Js]
5.0 x 1016 Hz
2.0 x 1016 Hz
5.0 x 1015 Hz
2.0 x 1015 Hz
No correct option
Selitys
∆E = hf
f = (∆E)/h = (5.44 x 10-19)/6.6 x 10-34 = 8.24 x 1014
f = (∆E)/h = (5.44 x 10-19)/6.6 x 10-34 = 8.24 x 1014