JAMB - Physics (2010 - No. 23)
An object is embedded in a block of ice, 10 cm below the plane surface. if the refractive index of the ice is 1.50, the apparent depth below the surface is?
2.50 cm
6.67 cm
7.50 cm
7.63 cm
Selitys
Refraction index, n = (real depth)/apparent depth
1.5 = (10)/X
X = (10)/1.5 = 6.67 cm
1.5 = (10)/X
X = (10)/1.5 = 6.67 cm