JAMB - Physics (2004 - No. 18)
Given three capacitors 0.3μF, 0.5μF and 0.2μF, the joint capacitance when arranged to give minimum capacitance is
0.1μF
0.3μF
1.0μF
0.5μF
Selitys
1/C = 1/0.3 + 1/0.5 + 1/0.2 = 10.3333
=> C = 1 / 10.3333 = 0.09677
≅ 0.1μF
∴ C = 0.1μF
=> C = 1 / 10.3333 = 0.09677
≅ 0.1μF
∴ C = 0.1μF