JAMB - Physics (1998 - No. 42)
In a nuclear fusion experiment, the loss of mass amounts to 1.0 x 10-6kg. The amount of energy obtained from the fusion is
3.0 x 10-4J
3.0 x 10-1J
9.0 x 104J
9.0 x 1010J
Selitys
Energy = mc2
= 1 x (3 x 108)2 x 106
= 9 x 1010J
= 1 x (3 x 108)2 x 106
= 9 x 1010J