JAMB - Physics (1994 - No. 28)
An object is placed directly below a glass block of thickness 3.0cm. Calculate the lateral displacement of the object if the refractive index of the glass is 1.5.
1.0cm
1.5cm
2.0cm
2.5cm
Selitys
1.5 = \(\frac{3}{\text {apparent displacement}}\)
Apparent depth = 2cm
displacement = 3 - 2
= 1cm
Apparent depth = 2cm
displacement = 3 - 2
= 1cm