JAMB - Physics (1991 - No. 35)
An equipment whose power is 1500W and resistance is 375 ohms would draw a current of
0.10A
2.00A
4.00A
77.5A
Selitys
P = I2R \(\Rightarrow\) I = \(\sqrt\frac{P}{R}\)
I = \(\sqrt\frac{1500}{375}\)
= 2A
I = \(\sqrt\frac{1500}{375}\)
= 2A