JAMB - Physics (1988 - No. 8)
How long will it take a 60kg man to climb a height of 22m if he expended energy at a rate of 0.25kW. [g = ms-2]
5.3s
34.5s
41.6s
52.8s
Selitys
power = mgh
0.25 x 103 = \(\frac {60 \times 10 \times 22}{t}\)
t = 52.8 sec
0.25 x 103 = \(\frac {60 \times 10 \times 22}{t}\)
t = 52.8 sec