JAMB - Physics (1987 - No. 29)
A pool of water appears to be 1.0m deep when viewed vertically from above. If the refractive index of water is 1.33, what is the actual depth of the pool?
0.750m
1.013m
1.330m
13.3000m
Selitys
n = \(\frac{\text {real depth}}{\text{apparent depth}}\)
1.33 = \(\frac{\text {real depth}}{1}\)
real depth = 1.33cm
1.33 = \(\frac{\text {real depth}}{1}\)
real depth = 1.33cm