JAMB - Mathematics (2017 - No. 40)
Simplify (\(\sqrt[3]{64a^3})^{-1}\)
4a
\(\frac{1}{8a}\)
8a
\(\frac{1}{4a}\)
Selitys
(\(\sqrt[3]{64a^3})^{-1}\)
\(\frac{1}{(\sqrt[3]{64a^3})}\)
= \(\frac{1}{4a}\)
\(\frac{1}{(\sqrt[3]{64a^3})}\)
= \(\frac{1}{4a}\)