JAMB - Mathematics (2011 - No. 37)
The sum of four consecutive integers is 34. Find the least of these numbers
7
6
8
5
Selitys
Let the numbers be a, a + 1, a + 2, a + 3
a + a + 1 + a + 2 + a + 3 = 34
4a = 34 - 6
4a = 28
a = \(\frac{28}{4}\)
= 7
The least of these numbers is a = 7
a + a + 1 + a + 2 + a + 3 = 34
4a = 34 - 6
4a = 28
a = \(\frac{28}{4}\)
= 7
The least of these numbers is a = 7