JAMB - Mathematics (1997 - No. 3)
Given that loga2 = 0.693 and loga3 = 1.097, find loga 13.5
1.404
1.790
2.598
2.790
Selitys
loga 13.5 = loga \(\frac{27}{2}\)
= 3loga 3 - log2a
= 3 x 1.097 - 0.693
= 2.598
= 3loga 3 - log2a
= 3 x 1.097 - 0.693
= 2.598