JAMB - Mathematics (1986 - No. 43)
120m2
576m3
816m3
1056m3
Selitys
Volume of solid = cross section x H
Since the cross section is a trapezium
= \(\frac{1}{2} (6 + 11) \times 12 \times 8\)
= 6 x 17 x 8 = 816m3
Since the cross section is a trapezium
= \(\frac{1}{2} (6 + 11) \times 12 \times 8\)
= 6 x 17 x 8 = 816m3