JAMB - Mathematics (1985 - No. 31)
Without using table, calculate the value of 1 + sec2 30o
2\(\frac{1}{3}\)
\(\frac{2}{15}\)
\(\frac{5}{3}\)
3\(\frac{1}{2}\)
Selitys
1 + sec2 30o = sec 30o
= \(\frac{2}{\sqrt{3}}\)
\(\frac{(2)^2}{3}\)
= \(\frac{4}{3}\)
1 + sec2 30o = sec 30o
= 1 + \(\frac{4}{3}\)
= 2\(\frac{1}{3}\)
= \(\frac{2}{\sqrt{3}}\)
\(\frac{(2)^2}{3}\)
= \(\frac{4}{3}\)
1 + sec2 30o = sec 30o
= 1 + \(\frac{4}{3}\)
= 2\(\frac{1}{3}\)