JAMB - Mathematics (1983 - No. 3)
Given a regular hexagon, calculate each interior angle of the hexagon
60o
30o
120o
45o
135o
Selitys
Sum of interior angles of polygon = (2n - 4)rt < s
sum of interior angles of an hexagon
(2 x 6 - 4) x 90o = (12 - 4) x 90o
= 8 x 90o
= 720o
each interior angle will have \(\frac{720^o}{6}\)
= 120o
sum of interior angles of an hexagon
(2 x 6 - 4) x 90o = (12 - 4) x 90o
= 8 x 90o
= 720o
each interior angle will have \(\frac{720^o}{6}\)
= 120o