JAMB - Mathematics (1980 - No. 25)
What will be the value of k so that the quadratic equation kx2 - 4x + 1 = 0 has two equal roots?
2
3
4
8
\(\frac{1}{4}\)
Selitys
kx2 - 4x + 1 = 0, comparing with ax2 + bx + c = 0
a = k, b = -4, c = 1 for equal root b2 = 4ac
(-4)2 = 4k
k = \(\frac{16}{4}\)
= 4
a = k, b = -4, c = 1 for equal root b2 = 4ac
(-4)2 = 4k
k = \(\frac{16}{4}\)
= 4