ExamPlay Dark Logo
Kirjaudu sisään

JAMB - Chemistry (2019 - No. 57)

Consider the reaction: A + 2B\(_{(g)} \rightleftharpoons \) 2C + D\(_{(g)}\) (\(\Delta\)H = +ve)

What will be the effect of decrease in temperature on the reaction?

Rate of backward reaction will increase
The equilibrium constant will shift
Rates of forward and backward reactions are not affected
Rate of forward reaction will increase

Selitys

The given reaction is endothermic, hence, a decrease in temperature will favor the exothermic side which is the backward reaction.

Kommentit (0)

Kirjaudu sisään kommentoidaksesi
Mainos
BrainBehindX Inc Logo
©2026; Powered By BrainBehindX Inc