JAMB - Chemistry (2007 - No. 13)
H\(_3\)PO\(_4\)(aq) + H\(_2\)O(l) ↔ H\(_2\)PO\(^{4-}\)(aq) + H\(_3\)O\(^+\)(aq) ΔH = -13kJ at 298K
In the reaction above, an increase in temperature would
In the reaction above, an increase in temperature would
slow down the reverse reaction
have no effect on the reaction
favour the reverse reaction
favour the forward reaction
Selitys
In an exothermic reaction, an increase in temperature will favour the reactants (shift the reaction towards the left), meaning the reaction will produce less product as heat is considered a product in an exothermic reaction; according to Le Chatelier's principle, the system will try to counteract the added heat by favouring the reactant side. Thus, the reverse reaction will be favoured.