WAEC - Physics (1997 - No. 8)
A piece of copper of mass 30g loses 60J of heat energy. If the specific heat capacity of copper is 400J\(kg^{-1}K^{-1}\), Calculate the change in the temperature of the copper
0.2K
0.8K
2K
4.5K
5K
توضیح
H=\(mc\Delta\theta \Rightarrow 60=0.03\times400\times\Delta\theta\\60= 12\Delta\theta therefore \Delta\theta=60/12 =5K\)