WAEC - Mathematics (2024 - No. 24)
A car valued at $ 600,000.00 depreciates by 10% each year. What will be the value of the car at the end of two years?
$ 120,000.00
$ 480,000.00
$ 486,000.00
$ 540,000.00
توضیح
Using P\(_n\) = P\(_o\)(1 - \(\frac{r}{100})^n\)
= 600,000(1 - \(\frac{10}{100})^2\)
= 600,000(0.90)\(^2\) = $486,000.00