WAEC - Mathematics (2010 - No. 13)
Given that \(\frac{5^{n +3}}{25^{2n -3}}\) = 5º, find n
n = 1
n = 2
n = 3
n = 5
توضیح
\(\frac{5^{n +3}}{25^{2n -3}} = 5^0\)
\(\frac{5^{n + 3}}{5^{2(2n - 3)}} = 5^0\)
n + 3 - 4n + 6 = 0
-3n + 9 = 0
-3n = -9
n = \(\frac{-9}{-3}\)
n = 3
\(\frac{5^{n + 3}}{5^{2(2n - 3)}} = 5^0\)
n + 3 - 4n + 6 = 0
-3n + 9 = 0
-3n = -9
n = \(\frac{-9}{-3}\)
n = 3