WAEC - Further Mathematics (2024 - No. 25)
Given that f(x) = x\(^2\) + 3x + 1, find the value of x at the turning point.
2
1\(\frac{1}{2}\)
-1\(\frac{1}{2}\)
-2
توضیح
Given that f(x) = x\(^2\) + 3x + 1
At turning point f"(x) = 0
f" = 2x + 3 = 0
= 2x = -3
x = \(\frac{-3}{2}\) = -1\(\frac{1}{2}\)