JEE Advance - Chemistry (1989 - No. 9)
The compound in which $$\mathop C\limits^* $$ uses its sp3 hybrid orbitals for bond formation is
H $$\mathop C\limits^* $$ OOH
(H2N)2 $$\mathop C\limits^* $$ O
(CH3)3 $$\mathop C\limits^* $$ OH
CH3 $$\mathop C\limits^* $$ HO