JAMB - Physics (2024 - No. 86)
At a pressure of 10\(^5\)Nm\(^{-2}\), a gas has a volume of 20m\(^3\). Calculate the volume at 4 x 10\(^5\)Nm\(^{-2}\) at constant temperature.
2m\(^3\)
3m\(^3\)
4m\(^3\)
5m\(^3\)
توضیح
Using \(P_1\) \(V_1\) = \(P_2\) \(V_2\)
\(V_2\) = \(\frac{P_1\times V_2}{P_2}\)
\(V_2\) = \(\frac{10^5\times 20}{4 \times 10^5}\)
\(V_2\) = 5m\(^3\)