JAMB - Physics (2024 - No. 110)

Two points on a velocity-time graph have coordinates (2s, 5m/s) and (4s, 15m/s). Calculate the mean acceleration

5.0ms\(^2\)

0.83ms\(^2\)

1.5ms\(^2\)

2.0ms\(^2\)

Mean acceleration = \(\frac{\Delta V}{\Delta t}\)

Point 1: (2s, 5m/s)
Point 2: (4s,15m/s)

Mean acceleration = \(\frac{ 15 - 5 }{4 - 2}\) = 5.0ms\(^2\)