JAMB - Mathematics (1993 - No. 15)
Solve the following equation (3x - 2)(5x - 4) = (3x - 2)2
\(\frac{-2}{3}\), 1
1
\(\frac{2}{3}\), 1
\(\frac{2}{3}\), \(\frac{4}{5}\)
توضیح
(3x - 2)(5x - 4) = (3x - 2)2 = 5x2 - 22x + 6
= 9x2 = 12x + 4
6x2 - 10x + 4 = 0
6x2 - 6x - 4x + 4 = 0
6x(x - 1) -4(x - 1) = (6x - 4)(x -1) = 0
x = 1 or \(\frac{2}{3}\)
= 9x2 = 12x + 4
6x2 - 10x + 4 = 0
6x2 - 6x - 4x + 4 = 0
6x(x - 1) -4(x - 1) = (6x - 4)(x -1) = 0
x = 1 or \(\frac{2}{3}\)