JAMB - Mathematics (1988 - No. 23)
A basket contain green, black and blue balls in the ratio 5 : 2 : 1. If there are 10 blue balls. Find the corresponding new ratio when 10 green and 10 black balls are removed from the basket
1 : 1 : 1
4 : 2 : 1
5 : 1 : 1
4 : 1 : 1
توضیح
Let x represent total number of balls in the basket.
If there are 10 blue balls, \(\frac{1}{8}\) of x = 10
x = 10 x 8 = 80 balls
Green balls will be \(\frac{5}{8}\) x 80 = 50 and black balls = \(\frac{2}{8}\) x 80 = 20
Ratio = Green : black : blue
50 : 20 : 10
-10 : -10 : -
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New Ratio 40 : 10 : 10
4 : 1 : 1
If there are 10 blue balls, \(\frac{1}{8}\) of x = 10
x = 10 x 8 = 80 balls
Green balls will be \(\frac{5}{8}\) x 80 = 50 and black balls = \(\frac{2}{8}\) x 80 = 20
Ratio = Green : black : blue
50 : 20 : 10
-10 : -10 : -
------------------
New Ratio 40 : 10 : 10
4 : 1 : 1