JAMB - Mathematics (1980 - No. 26)
Find the solution of the equation x + 2\(\sqrt{x} - 8\) = 0
(4, 16)
(2, 4)
(4, 1)
(1, 16)
(16, 16)
توضیح
x + 2\(\sqrt{x} - 8 = 0, Let \sqrt{x} = y\)
x = \(y^2\)
\(y^2 + 2y\) - 8 = 0
(y + 4)(x - 2) = 0
y = -4 or 2
x = 16 or 4
x = \(y^2\)
\(y^2 + 2y\) - 8 = 0
(y + 4)(x - 2) = 0
y = -4 or 2
x = 16 or 4