JAMB - Mathematics (1980 - No. 18)
Three numbers, x, y and z are connected by the relationships y = \(\frac{4x}{9}\) + 1. If x = 99, Find z = \(\frac{4y}{9}\) + 1
6\(\frac{1}{3}\)
20
21
176\(\frac{4}{9}\)
None of the above
توضیح
y = \(\frac{4x}{9}\) + 1, z = \(\frac{4y}{9}\) + 1, z = \(\frac{4}{9}\)(\(\frac{4}{9}\) x + 1) + 1
= [\(\frac{4}{9}\)(\(\frac{4}{9}\)(99) + 1]
= \(\frac{4}{9}\)(45) + 1
= 21
= [\(\frac{4}{9}\)(\(\frac{4}{9}\)(99) + 1]
= \(\frac{4}{9}\)(45) + 1
= 21