WAEC - Physics (2011 - No. 3)
A metal rod of density 7000 kgm-3 and cross-sectional area of 0.001257m2 has a mass of 1.76kg. Calculate its length.
0.20m
0.25m
0.40m
0.50m
Εξήγηση
P = \(\frac{M}{AL}\)
L = \(\frac{M}{CA}\)
= \(\frac{1.76}{7000 \times 0.001257}\)
= 0.2m
L = \(\frac{M}{CA}\)
= \(\frac{1.76}{7000 \times 0.001257}\)
= 0.2m