WAEC - Physics (2013 - No. 32)
A potential difference of 12V is applied across the ends of a 6\(\Omega\) resistor for 10 minutes. Determine the quantity of heat generated
720J
1200J
14400J
43200J
Erläuterung
Q = \(\frac{V^2 t}{R}
= \frac{12^2 \times 10 \times 60}{6}\)
= 14400J