WAEC - Physics (2001 - No. 36)
Three identical lamps each power 100W are connected in parallel across a potential difference of 250V. Calculate the current in the circuit
7.5A
2.5A
1.2A
0.8A
Erläuterung
P = IV
I = \(\frac{P}{V} = \frac{3 \times 100}{250} = 1.2A\)
I = \(\frac{P}{V} = \frac{3 \times 100}{250} = 1.2A\)