WAEC - Mathematics (1994 - No. 6)
Evaluate \( \frac{27^{\frac{1}{3}}}{16^{-\frac{1}{4}}} \)
6
5
4
3
2
Erläuterung
\(\frac{27^{\frac{1}{3}}}{16^{-\frac{1}{4}}} \)
= \(\frac{(3^3)^{\frac{1}{3}}}{(2^4)^{-\frac{1}{4}}}\)
= \(\frac{3}{2^{-1}}\)
= 6
\(\frac{27^{\frac{1}{3}}}{16^{-\frac{1}{4}}} \)
= \(\frac{(3^3)^{\frac{1}{3}}}{(2^4)^{-\frac{1}{4}}}\)
= \(\frac{3}{2^{-1}}\)
= 6