JEE MAIN - Physics (2002 - No. 48)
If there are $$n$$ capacitors in parallel connected to $$V$$ volt source, then the energy stored is equal to
$$CV$$
$${1 \over 2}nC{V^2}$$
$$C{V^2}$$
$${1 \over {2n}}C{V^2}$$
Erläuterung
The equivalent capacitance of $$n$$ identical capacitors of capacitance $$C$$ is equal to $$nC.$$ Energy stored in this capacitor
$$E = {1 \over 2}\left( {nC} \right){V^2} = {1 \over 2}nC{V^2}$$
$$E = {1 \over 2}\left( {nC} \right){V^2} = {1 \over 2}nC{V^2}$$