JAMB - Physics (2024 - No. 55)
Calculate the quantity of heat for copper rod whose thermal capacity is 400Jk\(^{-1}\) for a temperature change of 60ºC to 80ºC
2KJ
4KJ
6KJ
8KJ
Erläuterung
Quantity of Heat = heat capacity x change in temperature
Q = C\(_p\) x \(\Delta\)\(\theta\)
Q = 400 x 20 = 8000J = 8kJ