JAMB - Physics (1978 - No. 17)
The latent heat of fusion of ice is 80cal g-1. How much heat is required to change 10g of ice at QoC into water at the same temperature?
80 cal
10 cal
8 cal
800 cal
400 cal
Erläuterung
Quantity of heat = ml
= 10 x 80
= 800 cal
= 10 x 80
= 800 cal