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JAMB - Mathematics (1988 - No. 2)

If \(1P03{_4} = 115_{10}\) find P
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1
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3

Erläuterung

\(1 x 4^3 + P x 4^2 + 0 x 4 + 3 = 115_{10}\)

16p + 67 = 115 p = \(\frac{48}{16}\)

= 3

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