JAMB - Mathematics (1985 - No. 4)
In the equation below, Solve for x if all the numbers are in base 2: \(\frac{11}{x}\) = \(\frac{1000}{x + 101}\)
101
11
110
111
10
Erläuterung
\(\frac{11}{x}\) = \(\frac{1000}{x + 101}\) = 11(x + 101)
1000x = 11x + 1111
1000x - 11x = 1111
101x = 1111
x = \(\frac{1111}{101}\)
x = 11
1000x = 11x + 1111
1000x - 11x = 1111
101x = 1111
x = \(\frac{1111}{101}\)
x = 11