JAMB - Chemistry (2009 - No. 21)
The oxidation state of Cr in K\(_2\)Cr\(_2\)O\(_7\) is?
+7
+6
+5
4
Erläuterung
Potassium dichromate, K\(_2\)Cr\(_2\)O\(_7\)
→ [1 * 2] + [Cr * 2] + [-2 * 7] = 0
→ 2 + 2Cr - 14 = 0
→ 2Cr = 12
→Cr = \(\frac{12}{2}\) → 6
Potassium dichromate, K\(_2\)Cr\(_2\)O\(_7\)
→ [1 * 2] + [Cr * 2] + [-2 * 7] = 0
→ 2 + 2Cr - 14 = 0
→ 2Cr = 12
→Cr = \(\frac{12}{2}\) → 6